Let's first find the displacement of the bus when it accelerates:
d1=v0t+21at2,d1=0+21×2 s2m×(15 s)2=225 m.Then, we can find the displacement of the bus when it runs at a constant speed:
v=v0+at=0+2 s2m×25 s=50 sm,d2=v0t=50 sm×25 s=1250 m.Let's find the time that the bus takes to stop:
v=v0+at,t=av−v0=−3 s2m0 sm−50 sm=16.7 s.Then, we can find the displacement of the bus when it decelerates:
d3=v0t+21at2,d3=50 sm×16.7 s+21×(−3 s2m)×(16.7 s)2=417 m.Finally, we can find the total displacement travelled by the bus:
dtot=d1+d2+d3=225 m+1250 m+417 m=1892 m.
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