In a piston-cylinder arrangement, air with a volume of 0.1 m3 and a pressure of 100 kPa is compressed until pv2 = sbt until its pressure reaches 900 kPa. Find the volume of air in the final state and the work done during the process.
Solution;
Given ;
"pv^2=c"
"V_1=0.1m^3"
"P_1=100kPa"
"P_2=900kPa"
For final Temperature;
"P_1V_1^2=P_2V_2^2"
Hence;
"V_2=V_1(\\frac{P_1}{P_2})^{\\frac12}"
"V_2=0.1(\\frac{100}{900})^{0.5}"
"V_2=0.0333m^3"
The work done during the process;
"W_{1-2}=\\frac{P_2V_2-P_1V_1}{1-n}"
"W_{1-2}=\\frac{(900\u00d70.0333)-(100\u00d70.1)}{1-2}"
"W_{1-2}=-19.7kJ"
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