Answer to Question #227653 in Molecular Physics | Thermodynamics for Unknown346307

Question #227653

A diesel engine piston which has an area of 45 cm2 moves 5 cm during part

of suction stroke. 300 cm3 of fresh air is drawn in from the atmosphere. The pressure in the

cylinder during suction stroke is 0.9 × 105 N/m2 and the atmospheric pressure is 1.013 × 105 N/

m2. The difference between the suction and atmospheric pressure is accounted for flow resistance

in the suction pipe and inlet valve. Find the net work done during the process.


1
Expert's answer
2021-08-23T12:37:31-0400
W=(0.9105)(45104)(0.05)(1.013105)(300106)=10.14 JW=(0.9\cdot10^{5})(45\cdot10^{-4})(0.05)\\-(1.013\cdot10^{5})(300\cdot10^{-6})=-10.14\ J


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