Question

The pressure on 6dm³ volume of gas is 200kPa. What will be the volumn if the pressure is doubled, keeping the temperature constant

Answer 1

$V_1= 6 \;dm^3 \\ p_1= 200 \;kPa \\ p_2 = 2 \times 200 = 400 \;kPa \\ p_1V_1=p_2V_2 \\ V_2 = \frac{p_1V_1}{p_2} \\ = \frac{200 \times 6}{400} = 3 \;dm^3$

Answer: 3 dm³