If 20 g steam initially at 100 degree C is added to 60 g of ice initially at 0 degree C, then find the final
equilibrium temperature of the mixture.
Gives
"m_1=20g\\\\m_2=60g\\\\T_1=100\u00b0c\\\\T_2=0\u00b0c"
"T=\\frac{m_1T_1+m_2T_2}{m_1+m_2}"
"T=\\frac{20\\times100+60\\times0}{20+60}=\\frac{2000}{80}=25\u00b0c"
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