Question

If 20 g steam initially at 100 degree C is added to 60 g of ice initially at 0 degree C, then find the final

equilibrium temperature of the mixture.

Answer 1

Gives

$m_1=20g\\m_2=60g\\T_1=100°c\\T_2=0°c$

$T=\frac{m_1T_1+m_2T_2}{m_1+m_2}$

$T=\frac{20\times100+60\times0}{20+60}=\frac{2000}{80}=25°c$