Find the height in inches of the free surface if 0.8 ft3 of water is poured into a conical tank 20 inches high with a base radius of 10 inches. How much additional water in in3 is required to fill the tank?
_______ inches above the tank Answer in 2 decimal places
_______ in3
Volume of water (Vw) = 0.8 ft3 = 0.8 "\\times" 1728 in3 = 1382.4 in3
Radius of cone (r) = 10 in
height of cone (h) = 20 in
Volume of larger cone
"V_l = \\frac{1}{3} \\pi r^2 h \\\\\n\n= \\frac{\\pi \\times 10^2 \\times 20}{3} \\\\\n\n= 2094.39 \\;in^3"
Volume of smaller cone = "V_l - V_w"
"= 2094.39-1382.4 \\\\\n\n= 711.99\\; in^3"
from similar triangle concept
"\\frac{r_0}{h_0}= \\frac{10}{20} \\\\\n\nr_0=2h_0"
Volume of smaller cone can be written as
"\\frac{1}{3} \\pi r^2_0h_0 = 711.99 \\; in^3"
put the value of r o in the above equation
"\\frac{1}{3} \\pi (2h_0)^2h_0 = 711.99 \\;in^3 \\\\\n\nh_0 = 5.539 \\;in"
thus the height of the free surface = "h- h_0"
"=20-5.539 \\\\\n\n= 14.461 \\;in"
and the additional water required to fill the cone will be equal to the volume of the smaller cone
"V_{addition} = 711.99 \\;in^3"
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