Question

Two liquids of different densities (ρ₁ = 1500 kg/m³, ρ₂ = 500 kg/m³) are poured together into a 100-liter tank, filling it. If the resulting density of the mixture is 800 kg/m³, find the respective amounts of liquids used in kg.

m₁ =

m₂ =

Answer 1

$\rho_1=1500kg/m^3\\\rho_2=500kg/m^3\\\rho=800kg/m^3\\1liter=0.1m^3$

Weight of mixure =$\rho v$

Weight of mixure =$800\times0.1=80$

$x\rho_1+(0.1-x)\times\rho_2=80$

$x\times1500+(0.1-x)\times500=80$

$$1500x+50-500x=80\\1000x=30\\x=0.03$$

Weight=$80\times9.8=784N$

Mass$(m_1)=0.03\times1000=30kg\\(m_2)=0.07\times1000=70kg$