Question

Water enters the heater at 30^oC and leaves at 150^oF, what is the temperature difference in ^oC? answer in 2 decimal places

Answer 1

$T_1 = 30 \;°C \\ T_2 = 150 \;°F \\ T_2 = (150 \;°F -32) \times \frac{5}{9}=65.55 \;°C \\ ΔT= 65.55 -30 = 35.55 \;°C$