Question

what temperature gradient must exist in an aluminum rod for it to transmit 8.0 cal per second per cm

Answer 1

Question

What temperature gradient must exist in aluminium rod for it to transmit 8.0 cal per second per cm.

Solution;

P=$\frac {k×∆T×A}{L}$

p is power

k= thermal conductivity of Aluminium

Take k=205W/mK

∆T is temperature gradient.

L is the length.

Given:

$\frac P A$ =8.0cal/scm²=33.4864×10⁴W/sm²

$\frac {∆T}{L}=\frac PA\times \frac 1 k$

$\frac {∆T}{L}=\frac {33.4944×10^4}{205}$=1633.87K/m

Answer

∆T/L=1633.87K/m or 1360.87°C/m