A vessel of volume 0.2m3 contains nitrogen at 1.013 bar and 15°C. If 0.2 kg of nitrogen is now pumped into the vessel, calculate the new pressure when the vessel has returned to its initial temperature. The molar mass of nitrogen is 28 kg/K - mol and it may be assumed to be a perfect gas.
Solution.
V=0.2m3;V=0.2m^3;V=0.2m3;
p1=1.013⋅105Pa;p_1=1.013\sdot10^5Pa;p1=1.013⋅105Pa;
T=288K;T=288K;T=288K;
m2=0.2kg;m_2=0.2kg;m2=0.2kg;
M=28⋅10−3kg/mol;M=28\sdot10^{-3}kg/mol;M=28⋅10−3kg/mol;
p2V=m2MRT ⟹ p2=m2RTMV;p_2V=\dfrac{m_2}{M}RT\implies p_2=\dfrac{m_2RT}{MV};p2V=Mm2RT⟹p2=MVm2RT;
p2=0.2⋅8.31⋅28828⋅10−3⋅0.2=0.855⋅105Pa;p_2=\dfrac{0.2\sdot8.31\sdot288}{28\sdot10^{-3}\sdot0.2}=0.855\sdot10^5Pa;p2=28⋅10−3⋅0.20.2⋅8.31⋅288=0.855⋅105Pa;
p=p1+p2;p=p_1+p_2;p=p1+p2;
p=1.013⋅105Pa+0.855⋅105Pa=1.868⋅105Pa;p=1.013\sdot10^5Pa+0.855\sdot10^5Pa=1.868\sdot10^5Pa;p=1.013⋅105Pa+0.855⋅105Pa=1.868⋅105Pa;
Answer: p=1.868p=1.868p=1.868 bar.
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