Question #214635

The relative molecular mass of carbondioxide CO2 is 44. In an experiment, the value of γ for CO2 was found to be 1.3. Assuming that CO2 is a perfect gas, calculate the specific gas constant R and the specific heats at constant pressure cp and at constant volume, cv


1
Expert's answer
2021-07-08T09:57:46-0400

Solution.

M=44103kg/mol;M=44\sdot10^{-3}kg/mol;

γ=1.3\gamma=1.3 ;

R=R0M;R=\dfrac{R_0}{M};

R=8.3144103=188.9J/kgK;R=\dfrac{8.31}{44\sdot10^{-3}}=188.9J/kgK;

CV=Rγ1;C_V=\dfrac{R}{\gamma-1};

CV=188.91.31=629.7J/kgK;C_V=\dfrac{188.9}{1.3-1}=629.7J/kgK;

CPCV=R    Cp=R+CV;C_P-C_V=R\implies C_p=R+C_V;

CP=188.9+629.7=818.6J/kgK;C_P=188.9+629.7=818.6J/kgK;;

Answer: R=188.9J/kgK;R=188.9J/kgK;

CV=629.7J/kgK;C_V=629.7J/kgK;

CP=818.6J/kgK.C_P=818.6J/kgK.


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