The relative molecular mass of carbondioxide CO2 is 44. In an experiment, the value of γ for CO2 was found to be 1.3. Assuming that CO2 is a perfect gas, calculate the specific gas constant R and the specific heats at constant pressure cp and at constant volume, cv
Solution.
M=44⋅10−3kg/mol;M=44\sdot10^{-3}kg/mol;M=44⋅10−3kg/mol;
γ=1.3\gamma=1.3γ=1.3 ;
R=R0M;R=\dfrac{R_0}{M};R=MR0;
R=8.3144⋅10−3=188.9J/kgK;R=\dfrac{8.31}{44\sdot10^{-3}}=188.9J/kgK;R=44⋅10−38.31=188.9J/kgK;
CV=Rγ−1;C_V=\dfrac{R}{\gamma-1};CV=γ−1R;
CV=188.91.3−1=629.7J/kgK;C_V=\dfrac{188.9}{1.3-1}=629.7J/kgK;CV=1.3−1188.9=629.7J/kgK;
CP−CV=R ⟹ Cp=R+CV;C_P-C_V=R\implies C_p=R+C_V;CP−CV=R⟹Cp=R+CV;
CP=188.9+629.7=818.6J/kgK;C_P=188.9+629.7=818.6J/kgK;CP=188.9+629.7=818.6J/kgK;;
Answer: R=188.9J/kgK;R=188.9J/kgK;R=188.9J/kgK;
CV=629.7J/kgK;C_V=629.7J/kgK;CV=629.7J/kgK;
CP=818.6J/kgK.C_P=818.6J/kgK.CP=818.6J/kgK.
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