Question #213402

A rigid tank of volume 24 liters contains 0.2 kg of H2O originally at 2 bar. Find 

specific volume and initial temperature. What are the phases present (solid, 

liquid, vapor?). The tank was heated until its pressure reached 20 bar. Find work 

and heat exchanged during this process as well as final temperature


Expert's answer

Solution.

V=24103m3;V=24\sdot10^{-3}m^3;

m=0.2kg;m=0.2kg;

P1=2105Pa;P_1=2\sdot10^5Pa;

P2=20105Pa;P_2=20\sdot10^5Pa;

Vm=241030.2=0.12m3/kg;\dfrac{V}{m}=\dfrac{24\sdot10^{-3}}{0.2}=0.12m^3/kg;

M=18103kg/mol;M=18\sdot10^{-3}kg/mol;

PV=mMRT    T1=PVMmR;PV=\dfrac{m}{M}RT\implies T_1=\dfrac{PVM}{mR};

T1=210524103181030.28.31=52K;T_1=\dfrac{2\sdot10^{5}\sdot24\sdot10^{-3}\sdot18\sdot10^{-3}}{0.2\sdot8.31}=52K;

P1T1=P2T2;\dfrac{P_1}{T_1}=\dfrac{P_2}{T_2};

T2=T1P2P1=520201052105=520K;T_2=\dfrac{T_1P_2}{P_1}=\dfrac{520\sdot20\sdot10^5}{2\sdot10^5}=520K;

W=0;W=0;

Q=cVm(T2T1);Q=c_Vm(T_2-T_1);

cV=i2Rc_V=\dfrac{i}{2} R


Q=20.80.2468=1947J;Q=20.8\sdot0.2\sdot468=1947J;

Answer: Vm=0.12m3/kg;\dfrac{V}{m}=0.12m^3/kg;

T1=52K;T_1=52K;

W=0;W=0;

Q=1947J.Q=1947J.





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