Solution.
V=24⋅10−3m3;
m=0.2kg;
P1=2⋅105Pa;
P2=20⋅105Pa;
mV=0.224⋅10−3=0.12m3/kg;
M=18⋅10−3kg/mol;
PV=MmRT⟹T1=mRPVM;
T1=0.2⋅8.312⋅105⋅24⋅10−3⋅18⋅10−3=52K;
T1P1=T2P2;
T2=P1T1P2=2⋅105520⋅20⋅105=520K;
W=0;
Q=cVm(T2−T1);
cV=2iR
Q=20.8⋅0.2⋅468=1947J;
Answer: mV=0.12m3/kg;
T1=52K;
W=0;
Q=1947J.
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