.Air at 1 bar, 27oC and a rate of 0.4 kg/s enters a 10 cm diameter duct where it
is heated at constant pressure to reach 727oC at exit. Calculate outlet velocity
and deduce heat and work exchanged per second.
Gives
We know that
Av=dmdtAv=\frac{dm}{dt}Av=dtdm
Put value
v=dmdtAv=\frac{\frac{dm}{dt}}{A}v=Adtdm
v=0.47.85×10−3=50.95m/secv=\frac{0.4}{7.85\times10^{-3}}=50.95m/secv=7.85×10−30.4=50.95m/sec
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