a. shows a bead sliding on a wire, How large must height h1 be if the bead, starting at rest A, is to have a velocity of 200cm/s at point B? Ignore friction
When a bead has dropped a distance h it has lost potential energy = mgh, where m is the mass of the object, and g is the acceleration due to gravity, 9.8 "m\/s^2" . This potential energy will become kinetic energy "\\frac{1}{2}mv^2" .
"v = 200 \\;cm\/s = 2.00 \\;m\/s \\\\\n\nm \\times 9.8 \\times h = \\frac{1}{2} m \\times 2.0^2 = m \\times \\frac{4.00}{ 2} = m \\times 2 \\\\\n\nm \\times 9.8 \\times h = m \\times 2 \\\\\n\n9.8 \\times h = 2 \\\\\n\nh = \\frac{2}{9.8} = 0.204 \\;m = 20.4 \\;cm"
Answer: 20.4 cm
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Thanks so much, helped very much "
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