m1C1(0−T1)−ice heating to 0oCm1λ−ice meltingm1C2(T−0)−melted water heating m2C2(T−T2)−water coolingm3C3(T−T3)−copper cooling
m1C1(0−T1)+m1λ+m1C2(T−0)+m2C2(T−T2)+m3C3(T−T3)=0
0.031⋅2090⋅63+0.031⋅3.33⋅105+0.031⋅4186⋅T+0.589⋅2090⋅(T−26)+0.066⋅387⋅(T−26)=0
1386.328⋅T=18265.582T=13.18oC
Answer: T=13.18oC.
Comments