Answer to Question #152033 in Molecular Physics | Thermodynamics for Muhammad shehzad

Question

In a certain steam plant the turbine develop 703.72 kJ/kg . The heat supplied to the steam in the boiler is 2800 kJ/kg . The heat rejected by the steam to the cooling water in the condenser is 2100 kJ/kg and the net work of the cycle is -995 kW . Calculate the pump work in kj/kg and steam flow rate.

Answer 1

Answer

the pump work in kj/kg  is given by

$W=Q_1-Q_2=2800-2100$

$W=700KJ/kg$

steam flow rate is given as

$\frac{dQ}{dt}=\frac{dW}{dt}=995KJ/kg-sec$