Question #151894
A certain fuid at 10 bar is contained in a cylinder behind a piston the initial volume being 0.05m. Calculate the work done by the fuld when it expends reversibly) At constant pressure to a final volume of 0.2 m. ii) According to a linear law to a final volume of 0.2m '. & a final pressure of 2 bar. iii) According to a law (PV - constant) to a final volume of 0.1 m IV) According to a law (P. V3 = constant) to a final volume or 0.063 V) According to a law (P = (A / V2) ) - (B / V)) to a final volume of 0.1 m & final pressure of l bar where A, B are constants. Sketch all processes on (p - v) diagram
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Expert's answer
2020-12-21T10:43:37-0500

i) W=pΔV=1000000(0.20.05)=150(kJ)W=p\Delta V=1000000\cdot(0.2-0.05)=150(kJ)


ii) W=(200000+1000000)0.152=90(kJ)W=\frac{(200000+1000000)\cdot0.15}{2}=90(kJ)


iii) W=p1V1lnV2V1=10000000.05ln0.10.05=34.7(kJ)W=p_1V_1\ln\frac{V_2}{V_1}=1000000\cdot0.05\cdot\ln\frac{0.1}{0.05}=34.7(kJ)


iv) W=10000000.0531(1(0.050.063)31)=9253(J)W=\frac{1000000\cdot0.05}{3-1}(1-(\frac{0.05}{0.063})^{3-1})=9253(J)


v) W=pdV=(a/V2b/V)dV=10a0.6931b.W=\int pdV=\int(a/V^2-b/V)dV=10a-0.6931b.


From the initial conditions a=4000a=4000 and b=30000b=30000.


So, W=1040000.691330000=19200(J)W=10\cdot4000-0.6913\cdot30000=19200(J).









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