Solution.
Let x be the number of guests of the bride.
Let y the number of guests of the groom.
The bride can invite at most 60 guests:
"x\\le 60;"
I costs N$300 per guest on her side while it only costs N$150 per guest on the groom’s side and they have a budget of N$30000.
"300x+150y\\ge30000;"
Each guest on the bride’s side will receive 4 drink tickets and each guest from the groom’s side will receive 3 drink tickets and no more than 500 drink tickets can be given.
"4x+3y\\le500;"
Keeping in mind that both the bride and groom must have guests (neither of them can attend the wedding without any of their friends or family present).
"x\\ge0;"
"y\\ge0;"
This is a linear programming question. Combining all the equations as ontained above
"x\\le60;"
"300x+150y\\ge30000;"
"4x+3y\\le500;"
"x\\ge0;"
"y\\ge0;"
We build graphs of inequalities
i)Maximum number of guests-150;
ii)The bride has 50 guests and the groom has 100 guests .
Answer: i)Maximum number of guests-150;
ii)The bride has 50 guests and the groom has 100 guests.
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Thank you very much, you are amazing. May God bless you, this was really helpful,
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