first let's calculate the initial pressure by PV=nRT
P×10=1×8.3×300P=2490 pascalsP\times10=1\times8.3\times300\\P=2490\ pascalsP×10=1×8.3×300P=2490 pascals
Temperature being constant here which means we can apply boyle's law
PV= constant
P1V1=P2V2P_1V_1=P_2V_2\\P1V1=P2V2
2490×10=P2×5P2=1245 pascals2490\times10=P_2\times5\\P_2=1245\ pascals2490×10=P2×5P2=1245 pascals
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments