The total heat required to change 10 gram of ice at "-2^{\\circ}\\rm C" to water at "20^{\\circ}\\rm C" is given by
"Q=c_{ice}m(0^{\\circ}{\\rm C}-(-2^{\\circ}{\\rm C}))+\\lambda m+c_{water}m(20^{\\circ}{\\rm C}-0^{\\circ}{\\rm C})"
"Q=2100\\times 0.01\\times 2+334000\\times 0.01+4200\\times 0.01\\times 20"
"=4222\\:\\rm J."
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