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A string clamped at both ends, vibrates in a pattern of six loops at a frequency of 240 Hz. What frequency will cause it to vibrate in four loops?
The pattern of a standing wave consists of 5 loops. If the length of the string is L, then the distance between two consecutive node-antinode is:
A standing wave on a string of length L = 2 m has a wavelength λ = 0.5 m. The strings oscillates in its:
Two travelling waves y1(x,t) = A sin[k(x-vt)] and y2(x,t) = A sin[k(x+vt)] are superimposed on the same string. The distance between two adjacent nodes is:
A standing wave, generated on a string of length L, is represented by the following mathematical expression y(x,t) = 10 sin(2πx) cos(15πt). At what times would all the elements of the string have zero displacement [y(x,?) = 0]?
Consider a standing wave generated on a string of length L. If both frequency and linear mass density are kept the same while the tension in the string is divided by 4, then the new number of loops is:
A standing wave on a string has a frequency of 100 Hz, a wavelength of 0.04 m, and an amplitude of 2 mm. The transverse velocity of the point x = 0.02 m, is:
Given the wavefunction of a standing wave: y(x,t) = A sin(πx)cos(2πt), where x and y are in meters and t is in seconds. The position of the second anti-node from the end x = 0 is at:
A wave pulse travelling to the right along a thin cord reaches a discontinuity where the rope becomes thicker and denser. What is the orientation of the reflected and transmitted pulses?
Two interfering sinusoidal waves are described by the wavefunctions: y1 = A sin(kx-ωt) and y2 = A sin(kx-ωt+φ). If φ cannot exceed π/2 (0 ≤ φ ≤ π/2), then which of the following is true about the resultant amplitude Ares?
