Answer to Question #279414 in Mechanics | Relativity for Ahmad

Question

A standing wave on a string has a frequency of 100 Hz, a wavelength of 0.04 m, and an amplitude of 2 mm. The transverse velocity of the point x = 0.02 m, is:

Answer 1

Solution.

$\nu=100Hz;$

$\lambda=0.04m;$

$A=0.002m;$

$v-?;$

$v=\omega A;$

$\omega=2\pi\nu=2\sdot3.14\sdot100=628s^{-1};$

$v=628\sdot0.002=1.256 m/s;$

Answer:$v=1.256 m/s.$