Physics help (Kinetic Energy)
A bead with mass (1.8x10^-2)kg is moving along a wire in the positive direction of an x axis. Beginning at time=0, when the bead passes through x=0 with speed 12m/s, a constant force acts on the bead, the picture indicates the bead's position at these four times: t0=0 sec., t1=1.0 sec., t2=2.0 sec., t3=3.0 sec., The bead momentarily stops at t=3.0 sec. What's the kinetic energy of the bead as t=10 sec?
Do I use the K=(.5)mv^2 formula
or
the vf^2=vi^2+2ad formula, THEN the K-formula?