A 2-kg block slides on a frictionless horizontal surface and is connected on one side to a spring (k=40 N/m) as shown in the figure. The other side is connected via a massless rope to a 4-kg block that hangs vertically. The system starts from rest with the spring unextended. What is the maximum extension of the spring? What is the speed of the 4-kg block when the extension is 50 cm?
1
Expert's answer
2011-11-25T10:20:57-0500
Let's make the following denotations:
M1 = 2kg - first block mass M2 = 4kg - second& block mass E - extension of a spring
Let's find the extension of a spring at the state of equilibrium: g*M2 = k*E ==> E = g*M2/k = 9.8*4/40 = 0.98 m. So, the maximum extension of the spring is 98 cm.
Numbers and figures are an essential part of our world, necessary for almost everything we do every day. As important…
APPROVED BY CLIENTS
"assignmentexpert.com" is professional group of people in Math subjects! They did assignments in very high level of mathematical modelling in the best quality. Thanks a lot
Comments
Leave a comment