Answer to Question #99705 in Mechanics | Relativity for aisha

Question

The figure here shows an overhead view of three horizontal forces acting on a cargo canister that was initially stationary but that now moves across a frictionless floor. The force magnitudes are F1 = 2.90 N, F2 = 3.50 N, and F3 = 10.0 N, and the indicated angles are θ2 = 52.0 ˚ and θ3 = 30.0 ˚. What is the net work done on the canister by the three forces during the first 4.20 m of displacement?

Answer 1

We find work by the following formula:

$A=(F_1+F_2\cdot cos\theta_2+F_3\cdot cos \theta_3 )\cdot L$

$A=(2.9+3.5\cdot cos(52)+10\cdot cos(30) )\cdot 4.2 = 57.834 J$