according to the cosine theorem cosα=0.88,cosβ=0.69,sinα=0.47,sinβ=0.72.cos\alpha = 0.88, cos\beta = 0.69, sin\alpha = 0.47, sin\beta = 0.72.cosα=0.88,cosβ=0.69,sinα=0.47,sinβ=0.72.
from equilibrium T1cosβ=T2cosαT_1cos\beta = T_2cos\alphaT1cosβ=T2cosα , T1sinβ+T2sinα=mgT_1sin\beta + T_2sin\alpha = mgT1sinβ+T2sinα=mg
hence T1=92N,T2=72N.T_1 = 92N, T_2 = 72 N.T1=92N,T2=72N.
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A rope 5m long is fastened to two hooks 4m apart on a horizontal ceiling to the rope is attached a 10kg mass so that the segment of the rope is 3m and 2m. Compute the tension in each segment
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Dear visitor, please use panel for submitting new questions
A rope 5m long is fastened to two hooks 4m apart on a horizontal ceiling to the rope is attached a 10kg mass so that the segment of the rope is 3m and 2m. Compute the tension in each segment