Question

A child standing on the floor of a balcony of a multi storey building, throws a ball straight upwards with an initial velocity of 10m/s. Assume the the floor is 25m high from the ground. Take g=9.8m/s/s.find the a.maximum height above the ground reached by the ball. B.velocity with which the ball strikes the ground

Answer 1

A.

$$H=h+\frac{v^2}{2g}$$

$$H=25+\frac{10^2}{2(9.8)}=30\ m$$

B.

$$V^2=v^2+2gh$$

$$V^2=10^2+2(9.8)(25)$$

$$V=24\frac{m}{s}$$