Question

what is the final velocity of a 150 kg motorcycle driven by a 50.0 kg rider, accelerated from rest for 11 s by an unbalanced force of 800.0 N South

Answer 1

The acceleration of the motorcycle

$$a=\frac{F}{m}=\frac{800\:\rm N}{200\:\rm kg}=4\:\rm m/s^2$$

The final velocity

$$v_f=v_i+at=0+4\rm m/s^2\times 11\: s=44\: m/s$$