Answer to Question #97917 in Mechanics | Relativity for qirat

Question

how the displacement of a vertically thrown ball varies with time

Answer 1

               If the body is thrown vertically up in the presence of an initial speed v_y1 = 0 (Fig.1).    It will move equally slowly with an acceleration  equal  to  a= −g = − 9,81  m/s²

 

                                                                     Fig.1

     When the body reaches a height equal to  H_max   then it has speed  v_y1 = 0  and acceleration g. It follows that the body will not be able to stay at this height, so it will go into a state of free fall.

     That is, a body thrown upwards is an equally slow motion, in which, after reaching  H_max  signs of movement are  reversed.

     The basic formulas for calculating the motion of a body thrown vertically up are

Speed at any given time  t                  

                            v  = v₀  - gt ,   m/s.

Moving at any time t                                                 

H= v₀t - gt²/2, m.

Coordinate at any time t                                             

y=y₀ +H= v0t - gt²/2, m