Question #97853

Consider the conservation of energy equation below.
ΔK + ΔU + ΔEint = W + Q + TMW + TMT + TET + TER
A ball of mass m falls from a height h to the floor.
(a) Identify the appropriate version of the equation above for the system of the ball and the Earth.
ΔEint = Q +TET + TER
or
ΔU = W
or
ΔK + ΔU = 0
or
ΔK = W
Use this equation to calculate the speed of the ball just before it strikes the Earth. (Use the following as necessary: m for mass, h for height, g for acceleration due to gravity.)
v =

(b) Identify the appropriate version of the equation above for the system of the ball.
ΔK = W
or
ΔEint = Q +TET + TER
or
ΔU = W
or
ΔK + ΔU = 0
Use this equation to calculate the speed of the ball just before it strikes the Earth. (Use the following as necessary: m for mass, h for height, g for acceleration due to gravity.)

Expert's answer

(a) Since the ball falls from some height, it has potential energy, which turns into kinetic energy. Thus, the ball increases its kinetic energy by "consuming" its potential energy:


ΔK+ΔU=0,12mv2mgh=0,v=2gh.\Delta K+\Delta U=0,\\ \frac{1}{2}mv^2-mgh=0,\\ v=\sqrt{2gh}.

(b) The kinetic energy equals the work done by the gravitational field:


ΔK=W,12mvf212mvi2=mgh,12mvf20=mgh,v=2gh.\Delta K=W,\\ \frac{1}{2}mv_f^2-\frac{1}{2}mv_i^2=mgh,\\ \frac{1}{2}mv_f^2-0=mgh,\\ v=\sqrt{2gh}.
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