Question #96938

A wire of length 2m and radius 2mm is fixed to the center of wheel a torque of magnitude 0.0395Nm is applied to twist the wire find the regidity modulus of wire if angular twist is 0.038radian

Expert's answer

Rigidity modulus of wire


We need to find the rigidity modulus of wire if angular twist is 0.038 radian


Solution:


Length of the wire = l = 2 m


Angular twist = θ\theta = 0.038 radians


Torque magnitude = T{T} = 0.0395 Nm


Rigidity modulus = G{G}


Torsion constant =

J=12πr4{J} =\frac { 1 } {2} \pi r^4

It depends on the radius of the radius of the wire


Here,

r=2mm=2×103mr = 2 mm = 2 \times 10^{-3} m



Plug this r in the equation of J


J=12πr4=12π(2×103)4=2.52×1011m4{J} =\frac { 1 } {2} \pi r^4 =\frac {1}{2} \pi(2 \times 10^{-3})^4 = 2.52 \times 10^{-11} m^4

We know the formula for Rigidity modulus



G=TlθJ=0.0395×20.038×2.52×1011{G} =\frac {T l} {\theta J} = \frac {0.0395 \times 2} {0.038 \times2.52\times 10^{-11}}


G=8.2×1010Nm2{G} = 8.2 \times 10^{10} \frac {N} {m^2}

Answer:

Rigidity modulus =

G=8.2×1010Nm2{G} = 8.2 \times 10^{10} \frac {N} {m^2}


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