Answer to Question #96040 in Mechanics | Relativity for sarah

Question #96040
To win the game, a place kicker must kick a
football from a point 28 m (30.6208 yd) from
the goal, and the ball must clear the crossbar,
which is 3.05 m high. When kicked, the ball
leaves the ground with a speed of 18 m/s at
an angle of 49.4◦from the horizontal.The acceleration of gravity is 9.8 m/s2.
By how much vertical distance does the ball
clear the crossbar?
Answer in units of m.
1
Expert's answer
2019-10-08T10:08:38-0400
y=yi+vcos49.4°t0.5gt2y=y_i+v\cos{49.4\degree}t-0.5gt^2

t=xvsin49.4°=2818sin49.4°=2.049 st=\frac{x}{v\sin{49.4\degree}}=\frac{28}{18\sin{49.4\degree}}=2.049\ s

y=0+18cos49.4°(2.049)0.5(9.8)(2.049)2=3.43 my=0+18\cos{49.4\degree}(2.049)-0.5(9.8)(2.049)^2=3.43\ m

yh=3.433.05=0.38 my-h=3.43-3.05=0.38\ m


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