Question

Two airplanes leave an airport at the same
time. The velocity of the first airplane is
730 m/h at a heading of 44.3◦. The velocity
of the second is 590 m/h at a heading of 83◦.
How far apart are they after 2.9 h?
Answer in units of m.

Answer 1

$$d_1=730(2.9)=2117\ km$$

$$d_2=590(2.9)=1711\ km$$

$$d=\sqrt{2117^2+1711^2+2(2117)(1711)\cos{(83-44.3)\degree}}=3614\ m$$