Answer to Question #78002 in Mechanics | Relativity for Khyu

Question

A particle moving in a straight line with constant acceleration passes in succession A,B,C. The time taken from A to B is t and from B to C is 2t, AB = a, BC = b. Prove that the acceleration is (b-2a)÷(3t^2) and find the velocity at B. Assuming the initial velocity equals to u.