Question #71162

Solution a empty glass test tube is floted vertically in water depth 5 cm. Now on introducing a8cm liquid column in the tube its depth water is furthe increase by 4 cm now if the empty test tube is allow to float vertically in liquid 5cm of the tube is seen in air, find the total length of the tube
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Expert's answer

2017-11-30T16:04:07-0500

Answer on Question #71162-Physics-Mechanics-Relativity

1. Solution a empty glass test tube is floated vertically in water depth 5 cm.

2. Now on introducing a 8 cm liquid column in the tube its depth water is further increase by 4 cm.

3. Now if the empty test tube is allow to float vertically in liquid 5 cm of the tube is seen in air, find the total length of the tube

Solution

1.


ρTgAh=ρWatergA(5)\rho_{T} g A h = \rho_{\text{Water}} g A (5)ρT=5ρWaterh.\rho_{T} = \frac{5 \rho_{\text{Water}}}{h}.


2.


ρLgA(8)=ρWatergA(4)\rho_{L} g A (8) = \rho_{\text{Water}} g A (4)ρL=12ρWater.\rho_{L} = \frac{1}{2} \rho_{\text{Water}}.


3.


ρTgAh=(h5)ρLgA\rho_{T} g A h = (h - 5) \rho_{L} g A5ρWaterhgAh=(h5)12ρWatergA\frac{5 \rho_{\text{Water}}}{h} g A h = (h - 5) \frac{1}{2} \rho_{\text{Water}} g A5=(h5)125 = (h - 5) \frac{1}{2}h5=10h - 5 = 10h=15 cm.h = 15 \text{ cm}.


Answer: 15 cm.

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