A car goes at a constant 16 m/s up a hill. the frictional force is 500N. The height of the hill is .3 km and it the car travels a distance of 4.8 km. What is the work done in order to get to the top of the hill.?
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Expert's answer
2017-11-24T14:49:07-0500
v=16〖ms〗^(-1) "h\=" 3"km" "l\=" 4"\." 8"km" "g\=\1\0" 〖"ms" 〗^(-2) F=500N A-? A work A done by traction force of the car consist of two terms A=A_1+A_2, where A_1=mgh - work done against gravity and A_2=F_fr l=500⋅4800=2400(kJ) - work done against frictional force. To calculate A_1=mgh we need to know a mass mof a car. Answer: A=2400kJ+mgh
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