Question #312990

An old rope can now only safely suspended 120 kg. When the rope is tied to a beam, it hangs down with a vertical length of 12.0 m. Calculate the minimum time required for an 85kg person starting from rest to climb the entire length of the rope without breaking it


1
Expert's answer
2022-03-23T07:16:23-0400

Explanations & Calculations


  • The person can clime at some acceleration that would cause tension on the rope which is the maximum bearable.
  • If that acceleration is taken as a\small a then by applying F = ma for the man's climb upwards

Tmg=maa=120×9.8ms285kg×9.8ms285kg=4.0ms2\qquad\qquad \begin{aligned} \small T-mg&=\small ma\\ \small a&=\small \frac{120\times9.8\,ms^{-2}-85\,kg\times9.8\,ms^{-2}}{85\,kg}\\ &=\small 4.0\,ms^{-2} \end{aligned}

  • Then at this acceleration, he could climb the rope at a time of (using s = ut+1/2at^2)

12.0m=0+12×4.0ms2×t2t=2.4s\qquad\qquad \begin{aligned} \small 12.0\,m&=\small 0+\frac{1}{2}\times4.0\,ms^{-2}\times t^2\\ \small t &=\small 2.4\,s \end{aligned}


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