Question #312990

An old rope can now only safely suspended 120 kg. When the rope is tied to a beam, it hangs down with a vertical length of 12.0 m. Calculate the minimum time required for an 85kg person starting from rest to climb the entire length of the rope without breaking it


Expert's answer

Explanations & Calculations


  • The person can clime at some acceleration that would cause tension on the rope which is the maximum bearable.
  • If that acceleration is taken as a\small a then by applying F = ma for the man's climb upwards

Tmg=maa=120×9.8ms285kg×9.8ms285kg=4.0ms2\qquad\qquad \begin{aligned} \small T-mg&=\small ma\\ \small a&=\small \frac{120\times9.8\,ms^{-2}-85\,kg\times9.8\,ms^{-2}}{85\,kg}\\ &=\small 4.0\,ms^{-2} \end{aligned}

  • Then at this acceleration, he could climb the rope at a time of (using s = ut+1/2at^2)

12.0m=0+12×4.0ms2×t2t=2.4s\qquad\qquad \begin{aligned} \small 12.0\,m&=\small 0+\frac{1}{2}\times4.0\,ms^{-2}\times t^2\\ \small t &=\small 2.4\,s \end{aligned}


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