Question #312281

A learner mass(75 kg) is standing next to the road and sees a stationary car (mass 25kgl in front of her.she decides to run towards the car and jump on it and roll down the street.The learner accelerates at a constant acceleration of 2m/s calculate the car'a velocity just after the learner jumped on it

1
Expert's answer
2022-03-20T18:49:54-0400

m1v=(m1+m2)u,m_1v=(m_1+m_2)u,

u=vm1m1+m2=1.5 ms.u=v\frac{m_1}{m_1+m_2}=1.5~\frac ms.


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