An object with an initial velocity of 20 m/s accelerates uniformly at 5 m/s 2 in the direction of its motion at a distance of 10 m. What is the final velocity of the object?
vf2=vi2+2asv_f^2=v_i^2+2asvf2=vi2+2as
vf=vi2+2as=(20 m/s)2+2×5 m/s2×10 m=22.4 m/sv_f=\sqrt{v_i^2+2as}=\sqrt{(20\ m/s)^2+2\times5\ m/s^2\times10\ m}=22.4\ m/svf=vi2+2as=(20 m/s)2+2×5 m/s2×10 m=22.4 m/s
Answer: 22.4 m/s
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