Question #310638

A train starts from a station at point A and accelerates uniformly to a speed of 20m/s. It maintains this speed and then retards uniformly until it comes to rest at point B. The distance between the stations is 2000m the total time taken is 2 minutes.if the acceleration is twice the retardation. a) draw a velocity time graph. b) find the time for which the train is moving at constant speed. c) find it's retardation


1
Expert's answer
2022-03-13T18:46:44-0400

Solution.

v0=0m/s;v_0=0 m/s;

v=20m/s;v=20 m/s;

a=2a1;a=2a_1;

t=120s;t=120s;

a)a)

b)v22a+v22a1+vτ=2000;b)\dfrac{v^2}{2a}+\dfrac{v^2}{2a_1}+v\tau=2000;

v2a+va1+τ=120;\dfrac{v}{2a}+\dfrac{v}{a_1}+\tau=120;

3v2+4a1vτ=8000a1;3v^2+4a_1v\tau=8000a_1;

3v+2a1τ=240a1;3v+2a_1\tau=240a_1;

1200+80a1τ=8000a1;1200+80a_1\tau=8000a_1;

60+2a1τ=240a1;60+2a_1\tau=240a_1; |40\sdot40

1200+80a1τ=8000a1;1200+80a_1\tau=8000a_1;

2400+80a1τ=9600a1;2400+80a_1\tau=9600a_1;

1200=1600a1;-1200=-1600a_1;

a1=0.75m/s2;a_1=0.75 m/s^2;

2a1τ=240a13v;2a_1\tau=240a_1-3v;

τ=2400.756020.75=80s;\tau=\dfrac{240\sdot0.75-60}{2\sdot0.75}=80s;

c)a1=0.75m/s2;c)a_1=0.75 m/s^2;

Answer: b)τ=80s;b)\tau=80s;

c)0.75m/s2.c)0.75 m/s^2.


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