A ball is kicked such that it leaves the ground at an upwards angle of 35° above the horizontal with an initial velocity of 17 ms
How far away does the ball hit the ground?
Range
R=u2sin(2θ)2gR=\frac{u^2sin(2\theta)}{2g}R=2gu2sin(2θ)
R=172sin(70)9.8=27.71mR=\frac{17^2sin(70)}{9.8}=27.71mR=9.8172sin(70)=27.71m
R=R=R= 27.71m
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