Question #283899

An 85-kg runner is accelerating at a rate of 2 m/s^2 and a 65-kg runner at a rate of 3 m/s^2. If the heavier runner started at a speed of 1 m/s while the lighter runner started off stationary, then how long is it before the runners have the same momentum?


1
Expert's answer
2022-01-02T18:28:49-0500

Answer

Mass of first runner m1=85Kg

Initial velocity u1=1msec\frac{m}{sec}

Accereation a1=2 msec2\frac{m}{sec^2}

For second runner

Mass m2=65Kg

Initial velocity u2=0(staionary)

Acceleration a2=3msec3\frac{m}{sec}

For given case momentum is same after t time velocities

For first runner

v1=u1+at=1+2tv_1=u_1+at\\=1+2t

Similiarly

v2=u2+at=0+3tv_2=u_2+at\\=0+3t

Now given is that momentum is same after t time.

m1v1=m2v2m_1v_1=m_2v_2\\

v1v2=m2m1=6585\frac{v_1}{v_2}=\frac{m_2}{m_1}=\frac{65}{85}


Putting velocity value

3t1+2t=1317\frac{3t}{1+2t}=\frac{13}{17}

Now solving this equation we get value of t=3.4 sec.



Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS