Answer to Question #257322 in Mechanics | Relativity for Hemanth

Question #257322
Two wooden box beams (A and B) have the same outside dimensions (bh) and the same thickness t throughout, as shown in the figure. Both beams are formed by nailing. with each nail having an allowable shear load of f ball The beams are designed for a shear force of V. The magnitudes of the different parameters are: b=190 mm h=320 mm.t=24 mm f nall =250 N and V = 3kN
1
Expert's answer
2021-10-28T08:53:13-0400

I=112(bh3b1h13)=340.69106 mm4,I=\frac 1{12}(bh^3-b_1h_1^3)=340.69\cdot 10^6~mm^4,

2Fs=VQI,    smax=2FIVQ,\frac{2F}s=\frac{VQ}I,\implies s_{max}=\frac{2FI}{VQ},

a)

Q=Apdp=btht2=680103 mm3,Q=A_pd_p=bt\frac{h-t}2=680\cdot 10^3~mm^3,

sA=78.3 mm,s_A=78.3~mm,

b)

Q=Afdf=(b2t)tht2=544103 mm3,Q=A_fd_f=(b-2t)t\frac{h-t}2=544\cdot 10^3~mm^3,

sB=97.9 mm,s_B=97.9~mm,

c)

sB>sAs_B>s_A beam B is more efficient.


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