"I=\\frac 1{12}(bh^3-b_1h_1^3)=340.69\\cdot 10^6~mm^4,"
"\\frac{2F}s=\\frac{VQ}I,\\implies s_{max}=\\frac{2FI}{VQ},"
a)
"Q=A_pd_p=bt\\frac{h-t}2=680\\cdot 10^3~mm^3,"
"s_A=78.3~mm,"
b)
"Q=A_fd_f=(b-2t)t\\frac{h-t}2=544\\cdot 10^3~mm^3,"
"s_B=97.9~mm,"
c)
"s_B>s_A" beam B is more efficient.
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