Question

A object was fired at 17meters per second at a 40 degree and traveled 29 meters how long was it in the air

Answer 1

Let's first find the time that the object takes to reach the maximum height:

$$v_y = v_{0y}-gt,$$ $$0=v_0sin\theta-gt,$$ $$t=\dfrac{v_0sin\theta}{g}.$$

Then, we can find the flight time of the object (how long was it in the air) as follows:

$$t_{flight}=2t=\dfrac{2v_0sin\theta}{g},$$ $$t_{flight}=\dfrac{2\times17\ \dfrac{m}{s}\times sin40^{\circ}}{9.8\ \dfrac{m}{s^2}}=2.23\ s.$$