Answer to Question #252021 in Mechanics | Relativity for Kie

Question

A sky jumper speeds down a slope and exits the ski track in a horizontal direction with a velocity of 25 m/s where the landing incline falls off with a slope of 33°. Solve the following:

A. What is the half time of flight of the sky jumper?

B. What is the range of the sky jumper when it lands?

Answer 1

$h=gt^2/2$

$l=vt$

$h=l\cdot\tan33°\to gt^2/2=vt\cdot\tan33°$

$t=2v\tan33°/g=2\cdot25\cdot\tan33°/9.8=3.31\ (s)$

$t_{1/2}=1.66\ (s)$ . Answer

$l=25\cdot3.31=82.75 \ (m)$ . Answer