Question

A football is kicked with an initial velocity of 20 m/s at an angle of 50-degrees with the horizontal. Determine the time of flight, the horizontal distance, and the peak height of the football.

Answer 1

The time of flight

$T = \frac{2usin θ}{g} \\ = \frac{2 \times 20 \times sin 50°}{9.81} \\ = 3.12 \;s$

The horizontal distance

$R = \frac{u^2sin(2θ)}{g} \\ = \frac{20^2 \times sin(2(50°))}{9.81} \\ = 40.15\;m$

The peak height of the football

$H = \frac{u^2sin^2θ}{2g} \\ = \frac{20^2 \times sin^2(50°)}{2 \times 9.81} \\ = 11.96 \;m$