Question

A man walks on a astraight road from his house to a market 2.5 km away with a speed of 5 km/h. Finding the market closed he walks back home with a speed of 7.5 km/h. what is the magnitude of average velocity

Answer 1

The average velocity is the total displacement divided by total time:

$$v_\text{avg}=\frac{D}{t}=\frac{0}{t}=0.$$