Assume
P = 4 i ^ + 3 j ^ + 2 k ^ P=4\hat{i}+3\hat{j}+2\hat{k} P = 4 i ^ + 3 j ^ + 2 k ^
Q = 2 i ^ + 3 j ^ + k ^ Q=2\hat{i}+3\hat{j}+\hat{k} Q = 2 i ^ + 3 j ^ + k ^
∣ P ∣ = 16 + 9 + 4 = 30 ∣ Q ∣ = 4 + 9 + 1 = 14 |P|=\sqrt{16+9+4}=\sqrt{30}\\|Q|=\sqrt{4+9+1}=\sqrt{14} ∣ P ∣ = 16 + 9 + 4 = 30 ∣ Q ∣ = 4 + 9 + 1 = 14
P > Q P>Q P > Q correct statement
PQ=( 4 i ^ + 3 j ^ + 2 k ^ ) . ( 2 i ^ + 3 j ^ + k ^ ) (4\hat{i}+3\hat{j}+2\hat{k}).(2\hat{i}+3\hat{j}+\hat{k}) ( 4 i ^ + 3 j ^ + 2 k ^ ) . ( 2 i ^ + 3 j ^ + k ^ )
PQ=8+9+2=19
2.
A = 3 i ^ − j ^ + 2 k ^ B = 2 i ^ + 3 j ^ − k ^ A=3\hat{i}-\hat{j}+2\hat{k}\\B=2\hat{i}+3\hat{j}-\hat{k} A = 3 i ^ − j ^ + 2 k ^ B = 2 i ^ + 3 j ^ − k ^
A × B = ∣ i ^ j ^ k ^ 3 − 1 2 2 3 − 1 ∣ A\times B=\begin{vmatrix}
\hat{i} & \hat{j}&\hat{k} \\
3& -1&2\\2&3&-1
\end{vmatrix} A × B = ∣ ∣ i ^ 3 2 j ^ − 1 3 k ^ 2 − 1 ∣ ∣
A × B = i ^ ( 1 − 6 ) − j ^ ( − 3 − 4 ) + k ^ ( 9 + 2 ) A\times B=\hat{i}(1-6)-\hat{j}(-3-4)+\hat{k}(9+2) A × B = i ^ ( 1 − 6 ) − j ^ ( − 3 − 4 ) + k ^ ( 9 + 2 ) A × B = − 5 i ^ + 7 j ^ + 11 k ^ A\times B=-5\hat{i}+7\hat{j}+11\hat{k} A × B = − 5 i ^ + 7 j ^ + 11 k ^
(2)
2 A + 2 B = 2 × ( 3 i ^ − j ^ + 2 k ^ ) + 2 × ( 2 i ^ + 3 j ^ − k ^ ) 2A+2B=2\times(3\hat{i}-\hat{j}+2\hat{k})+2\times (2\hat{i}+3\hat{j}-\hat{k}) 2 A + 2 B = 2 × ( 3 i ^ − j ^ + 2 k ^ ) + 2 × ( 2 i ^ + 3 j ^ − k ^ ) ( 2 A + 2 B ) = 10 i ^ + 4 j ^ + 2 k ^ (2A+2B)=10\hat{i}+4\hat{j}+2\hat{k} ( 2 A + 2 B ) = 10 i ^ + 4 j ^ + 2 k ^
A × ( 2 A + 2 B ) = ∣ i ^ j ^ k ^ 3 − 1 2 10 4 2 ∣ A\times(2A+2B)=\begin{vmatrix}
\hat{i} & \hat{j}&\hat{k} \\
3& -1&2\\10&4&2
\end{vmatrix} A × ( 2 A + 2 B ) = ∣ ∣ i ^ 3 10 j ^ − 1 4 k ^ 2 2 ∣ ∣
A × ( 2 A + 2 B ) = i ^ ( − 2 − 6 ) − j ^ ( 6 − 20 ) + k ^ ( 12 + 10 ) = − 8 i ^ + 14 j ^ + 22 k ^ A\times(2A+2B)=\hat{i}(-2-6)-\hat{j}(6-20)+\hat{k}(12+10)=-8\hat{i}+14\hat{j}+22\hat{k} A × ( 2 A + 2 B ) = i ^ ( − 2 − 6 ) − j ^ ( 6 − 20 ) + k ^ ( 12 + 10 ) = − 8 i ^ + 14 j ^ + 22 k ^
A . B = ( 3 i ^ − j ^ + 2 k ^ ) . ( 2 i ^ + 3 j ^ − k ^ ) = 6 − 6 − 2 = − 2 A.B=(3\hat{i}-\hat{j}+2\hat{k}).(2\hat{i}+3\hat{j}-\hat{k})=6-6-2=-2 A . B = ( 3 i ^ − j ^ + 2 k ^ ) . ( 2 i ^ + 3 j ^ − k ^ ) = 6 − 6 − 2 = − 2
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