Gives
v=0.6c
Now
We know that
"\u2206x=x_0\\sqrt{1-\\frac{v^2}{c^2}}"
"\u2206x=x_0\\sqrt{1-\\frac{(0.6c)^2}{c^2}}"
"\u2206x= x_0\\sqrt{1-0.36}=0.8x_0"
Time
"\u2206t=\\frac{\u2206x}{v}"
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