Answer to Question #184431 in Mechanics | Relativity for shy

Question

a body of mass 80 g is attached to the end of a helical spring with a spring constant of 4500 dynes/cm, and is made to vibrate with an amplitude of 16 cm. calculate the period of vibration, the maximum velocity of the body, and the velocity of the body when it is 10 cm from the equilibrium position

Answer 1

$m=80\space g=80\times10^{-3}\space kg$

Spring Constant, $k=4500\space dynes/cm$$=4500\times10^{-3}\space N/m$

Amplitude, $A=16\space cm=16\times10^{-2}\space m$

Time Period, $T=2\pi mk$

$T=2\times3.14\times(80\times10^{-3})\times(4500\times10^{-3})=2.261\space s$

Maximum Velocity, $v_{max}=Akm=0.0576\space m/s$

Velocity at x=10cm,

$v=km(A-x)=0.0216\space m/s$